CLEVELAND, OH - The Cleveland Indians today announced that Double-A Akron RHP SHAWN ARMSTRONG has been named Indians Minor League Player of the Week for April 28-May 4. The Indians Player of the Week Award recognizes an individual performance from within the Indians Player Development System and is announced each Tuesday through the end of the Minor League season.
Armstrong, 23, has anchored the back end of the Akron bullpen over the club's recent 9-game win streak, notching a team-high 4 saves over 6.1 scoreless innings. Armstrong's 4 saves rank T6th in the Eastern League and are 3rd-most among all Tribe minor leaguers. His last save came on Sunday at Altoona, as the RubbersDucks completed a 4-game sweep over the Curve. The 6-foot-2, 215-pound righty has tossed 4.2 consecutive innings without allowing a hit, and has pitched 8.2 consecutive scoreless frames dating back to his first appearance of the season on April 8 at Altoona. On the season, Armstrong has allowed just one earned run across 9.2 innings (0.93 ERA) in 10 relief appearances.
Originally drafted by the Indians in the 18th round of the 2011 First-Year Player Draft, Armstrong entered the 2014 campaign with a career minor league record of 4-6 with a 2.45 ERA (29 ER/106.2 IP) over parts of 3 season in the Indians organization. The North Carolina native missed time during the 2013 regular season with an injury to his non-throwing hand, but went on to go 1-0 with a 1.59 ERA (2 ER/11.1 IP) in 10 games for the Surprise Saguaros in the Arizona Fall League.